[ORACLE]OVER함수를 이용한 SQL문

그 이전상태의 값을 가져오더라..

select
resident_no, user_id,status_g, reg_dt,
lag(status_g,1) over (partition by resident_no order by reg_dt) as status_g_prev,
lag(reg_dt,1) over (partition by resident_no order by reg_dt) as reg_dt_prev,
lag(user_id,1) over (partition by resident_no order by reg_dt) as uesr_id_prev
from crss_status_his